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For the reaction AB(2(g)) hArr AB((g)) +...

For the reaction `AB_(2(g)) hArr AB_((g)) + B_((g))` if `alpha` is negligiable w.rt 1 then degree of dissociation `(alpha)` of `AB_(2)` is proportional to

A

`1/p`

B

`1/v`

C

`1/(sqrt(p)`

D

`sqrt(v)`

Text Solution

Verified by Experts

The correct Answer is:
C, D
`underset((1-alpha))(AB_(2)) harr underset(alpha)(AB)+underset(alpha)(B)`
Total moles = `1+alpha`
`K_(P)=(Palpha^(2))/(1-alpha^(2)), alpha lt lt implies K_(P)=P alpha^(2) implies alpha(1)/(sqrt(P))` & `P alpha(1)/(V)`
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