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For the reaction in equilibrium: 2NOBr((...

For the reaction in equilibrium: `2NOBr_((g)) hArr 2NO_((g)) + Br_(2(g)) `If `P_(Br_(2)) `is `(P)/(9)` t equilibrium and P is total pressure, If `(P)/(Kp) = x^(2)` then what is x value.

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The correct Answer is:
9
`2NOBr_((g)) harr 2NO_((g))+Br_(2)`
pressure at equilibrium `P-(3P)/(9), (2P)/(9), (P)/(9)`
`P_(T)=(6P)/(9)+(2P)/(9)+(P)/(9)=P`
`K_(P)=(P^(2)NO.PBr_(2))/(P^(2)NOBr)=(((2p)/(9))^(2) xx P)/(((6P)/(9))^(2)) implies K_(P)=(P)/(81)`
Given `(P)/(K_(P))=x^(2), K_(P)=(P)/(x^(2))=(P)/(81) implies x=9`
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