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N(2)O(4) hArr 2NO(2). At 300K N(2)O(4) ...

`N_(2)O_(4) hArr 2NO_(2). ` At 300K `N_(2)O_(4)` at 6 atmosphere is heated to 600K where equilibrium is established with a total pressure of 16 atmospheres. What is `K_(p)` at 600K ?

Text Solution

Verified by Experts

The correct Answer is:
8
`underset(1-alpha)(1)(N_(2)O_(4(g))) harr underset(2alpha)underset(0)(2NO_(2(g)))`
Total no. of moles at equilibrium = `1+alpha`
From ideal gas equation
`underset("before equlibrium")((P_(1))/(n_(1)T_(1)))=underset("after equilibrium")((P_(2))/(n_(2)T_(2)))`
`(6)/(1 xx 300)=(16)/((1+alpha)600), alpha=(1)/(3)`
`implies K_(P)=(P^(2)NO_(2))/(PN_(2)O_(4))=8`
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