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In a reaction at equilibrium, x' mole of...

In a reaction at equilibrium, `x' mole of the reactant 'A' decompose to give I mole of C and D. It has been found that the fraction of A decomposed at equilibrium is independent of intial concentration of A. Find the value of x.

Text Solution

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The correct Answer is:
2
`IxA harr D+C`
`a(1-alpha), (a alpha)/(x), (a alpha)/(x)`
`K_(c)=(a^(2)alpha^(2))/(V^(2)x^(2)[(a(1-alpha))/(V)]^(x))=(alpha^(2)a^(2-x))/(x^(2)(1-alpha)x 2-x)`
`alpha` independent of a =2-x=0 `implies` x=2
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