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The graph relates in K(eq) Vs 1/T for a ...

The graph relates in `K_(eq) Vs 1/T` for a reaction. The reaction must be :

A

exothermic

B

endothermic

C

`DeltaH` is negligible

D

spontaneous

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta G^(@)=RT -RTl nk, l nk =(-DeltaH^(@))/(RT)+(deltaS^(@))/(R)`
`:.` slope= `(-DeltaH^(@))/(R)` = .+. Ve `implies DeltaH^(@) lt 0`
`:.` exothermic
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