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AT673 K. in the formation of NH(3) From ...

AT673 K. in the formation of `NH_(3)` From `N_(2) and H_(2)` , the partial pressures of `N_(2) , H_(2) and and NH_(3)` at equilibrium are 0.5 , 1 and `9 xx 10^(-3) ` atm respectively. `(N_(2) + 3H_(2) hArr + Q)`
Report `Delta K_(C)` Value

A

9.3 kcal

B

430 kcal

C

220 kcal

D

0.930 kcal

Text Solution

Verified by Experts

The correct Answer is:
D
`Delta G^(@)= -2.303 RT log K_(P)`
`=2.303 xx 2 xx 10^(-3) xx 673 log_(10)0.5`
= 0.929 K.cal
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