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For the reaction at 298K: A((g)) +B((g...

For the reaction at 298K: `A_((g)) +B_((g)) hArr C_((g)) + D_((g)) Delta H^(@) + `29.8kcal and `Delta S^(@) = 100cal K^(-1)`. Find the value of equilibrium constant.

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The correct Answer is:
5
`log(K_(2))/(K_(1))=(DeltaH)/(2.303R)[(1)/(T_(1))-(1)/(T_(2))]`
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