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The following equilibria are given N2+...

The following equilibria are given
`N_2+3H_2 harr 2NH_3 , K_c=K_1 , N_2+O_2 harr 2NO, k_c=K_2 , H_2+1/2 O_2 harr H_2O, K_C = K_3`
The equilibrium constant of the reaction. `2NH_3+5/2 O_2 harr 2NO+3H_2O` in the terms of `K_1,K_2` and `K_3` is

A

`K_1,K_2,K_3`

B

`K_1K_2//K_3`

C

`K_1K_3^2K_2`

D

`K_2K_3^3//K_1`

Text Solution

Verified by Experts

The correct Answer is:
D
`N_(2)+3H_(2) harr 2NH_(3), K_(1) to a`
`N_(2)+O_(2) harr 2NO, K_(2) to b`
`H_(2)+(1)/(2)O_(2) harr H_(2)O, K_(3) to c`
then `2NH_(3)+(5)/(2)O_(2) harr 2NO+3H_(2)O` is got by equation adding b+3c-a
i.e., `K=(K_(2)K_(3)^(3))/(K_(1))`
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