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At a given temperature, Ke is 4 for the ...

At a given temperature, Ke is 4 for the reaction `H_(2(g)) + CO_(2(g)) hArr H_(2)O_((g)) + CO_((g))`. Initially 0.6 moles each of `H_(2) and CO_(2)` are taken in 1lit flask. The equilibrium concentration of `H_(2) O_((g))` is

A

0.4M

B

0.46M

C

0.2M

D

0.8M

Text Solution

Verified by Experts

The correct Answer is:
A

`K_(c)=(x^(2))/((0.6-x)^(2))=4 implies (x)/(0.6-x)=2`
x=1.2-3x, 3x=1.2, `x=0.4=[H_(2)O]`
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