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The equilibrium constant of a chemical r...

The equilibrium constant of a chemical reaction

A

`(4alpha^(2)P)/(1-alpha^(2))`

B

`(4alpha^(2)P^(2))/(1-alpha^(2))`

C

`(4alpha^(2)P^(2))/(1-alpha)`

D

`(4alpha^(2)P)/(1-alpha)`

Text Solution

Verified by Experts

The correct Answer is:
A

total moles = `1+alpha`
`K_(P)=(P_(B)^(2))/(P_(A))=(((2alpha)/(a+alpha)P)^(2))/(((1-alpha)/(a+alpha)P))=(4alpha^(2))/(1-alpha^(2))P`
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