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3C(2)H(2) hArr C(6) H(6) the above react...

`3C_(2)H_(2) hArr C_(6) H_(6)` the above reaction is performed in a I lit vessel. Equilibrium is established when 0.5 mole of benzene is present at certain tempe-rature. If equilibrium constant is 4 `lit^(2) "mole"^(-2)` The total number ot moles of the substances present at cquilibrium,

A

0.5

B

1

C

1.5

D

2

Text Solution

Verified by Experts

The correct Answer is:
B
`3C_(2)H_(2(g)) harr C_(6)H_(6(g))`
`K_(c)=([C_(6)H_(6)])/([C_(2)H_(2)]^(3)), 4=(0.5)/([C_(2)H_(2)]^(3)) implies [C_(2)H_(2)]^(3)=(1)/(8)`
`[C_(2)H_(5)]=0.5=(n)/(v) implies n=0.5`
Total no. of moles of `C_(2)H_(2)` & `C_(6)H_(6)` at equilibrium = 0.5+0.5=1
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