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At a certain temperature, the degree of ...

At a certain temperature, the degree of dissociation of `PCI_(5)` was found to be 0.25 under a total pressure of 15 atm. The value of `K_(P)` for the dissociation of `PCl_(5)` is

A

1

B

0.25

C

0.5

D

0.75

Text Solution

Verified by Experts

The correct Answer is:
A

Given `alpha = 0.25`
Total no. of moles at equilibrium = `1+alpha=1.25`
Total pressure = 15 atm
`K_(P)=(P_(PCl_(3)) xx P_(Cl_(2)))/(P_(PCl_(5)))=(((0.25)/(1.25) xx 15)xx((0.25)/(1.25) xx 15))/(((0.75)/(1.25) xx 15))=1`
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