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Vapour density of PCl(5) is 104.16 but w...

Vapour density of `PCl_(5)` is 104.16 but when heated at `230^(@) C` its vapour density is reduced to 62 . The degree of dissociation of `PCl_(5)` at this temperature will be

A

% `alpha`=68%

B

average molecular mass of mixture of gases is 124

C

pressure ratio of `PCI_(5)` to `PCI_(3)` is 32 : 68

D

total moles at equilibrium may be 1.68 times of initial moles of `PCI_(5)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
`underset(1-alpha)(PCl_(5(g))) harr underset(alpha)(PCl_(3(g)))+underset(alpha)(Cl_(2(g)))`
`alpha=(D-d)/(d(n-1))=(104.25-62)/(62)=0.68`
Total no. of moles = `1+alpha` = 1.68
average molecular weight = `2 xx "vapour density"=124`
pressure ratio of `PCl_(5) : PCl_(3)`
0.32 : 0.68
32 : 68 `( :. p alpha n)`
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