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In a 7.0 Levacuated chamber, 0.50 mol H(...

In a 7.0 Levacuated chamber, 0.50 mol `H_(2)` and 0.50 mol `I_(2)` react at `427^(@)` C.
`H_(2) (g) + I_(2) (g) hArr HI (g) ` + Heat , At the given temperature, `K_(c)` = 49 for the reaction.
what is the value of `K_(p)` ?

A

7

B

49

C

24.5

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`K_(P)=K_(c), Delta ng =0`
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