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One mole of A (g) is heated to 200^@ C i...

One mole of A (g) is heated to `200^@` C in a one litre closed flask, till the following equilibrium is reached.
`A(g) leftrightarrow B(g)`
The rate of forward reaction, at equilibrium, is 0.02 ` mol L^(-1) mi n^(-1)`. What is the rate (in ` mol L^(-1)mi n^(-1)`) of the backward reaction at equilibrium?

Text Solution

Verified by Experts

The correct Answer is:
2

`[B]=x=0.5 implies [A]=0.5`
`K=(K_(f))/(K_(b))=(0.5)/(0.5)=1`
`implies K_(b)=K_(f)=0.02=2xx10^(-2)`
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