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In the reaction, C((s)) + CO(2(g)) harr ...

In the reaction, `C_((s)) + CO_(2(g)) harr 2CO_((g))` the equilibrium pressure is 12 atm. If 50% of `CO_(2)` reacts, calculate `K_(P)`. If `K_(P)= y^(2)` then what is 'y" ?

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The correct Answer is:
4

total pressure = `(3P)/(2)=12 implies P=8` atm
`:. K_(P)=((8)^(2))/((4))=4`
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