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One mole of N(2) and 3 mole of PCI(5) ar...

One mole of `N_(2)` and 3 mole of `PCI_(5)` are placed in a 100 litre vessel heated to `227^(@)`c. The equilibrium pressure is 2.05 atm. Assuming ideal behaviour, If `K_(p)` of the reaction `PCl_(5) hArr PCl_(3)+Cl_(2)` is `y xx 10^(-1)` then what is 'y'?

Text Solution

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The correct Answer is:
2

Total no. of moles at equilibrium = 4+x
Given, total pressure at equilibrium = 2.05
Now PV=nRT (at equilibrium)
`2.05 xx 100=(4+x)0.0821 xx 500`, x = 0.9939
Now degree of dissociation of `PCl_(5)=("Mole dissociation")/("Total mole")=(0.9939)/(3)=0.3313`
`:. K_(P)=[(""^(n)PCl_(3) xx ""^(n)Cl_(2))/(""^(n)PCl_(5))] xx [(P)/(sum n)]^(+1)`
`=(x^(2))/((3-x)) xx ((2.05)/(4+x))`
`=0.2 = 2 xx 10^(-1)=y xx 10^(-1) implies y=2`
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