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A sample of N(2)O(4(g)) with a pressure ...

A sample of `N_(2)O_(4(g))` with a pressure of I atm is placed in a flask. When equilibrium is reached, 20% `N_(2)O_(4(g))` has been converted to `NO_(2(g)) .N_(2)O_(4(g)) hArr 2NO_(2(g))`, If the orginal pressure is made 10% of the earlier, then percent dissociation will be

A

0.2

B

0.42

C

0.54

D

0.62

Text Solution

Verified by Experts

The correct Answer is:
C

Parpal pressure `((1-x)/(1+x))P, ((2x)/(1+x))P`
`K_(P)=(4x^(2)P)/(1-x^(2))`
In case-I: P=1 atm and x = 0.20
In case II : P=0.1 atm 10% of the earlier pressure and x=?
`(4(0.2)^(2) xx 1)/([1-(0.2)^(2)])=(4x^(2)(0.1))/(1-x^(2))`
`(0.04)/(1-0.04)=(x^(2)(0.1))/((1-x^(2)))(x^(2))/(1-x^(2))=0.4167`
`x^(2)=0.2941, x=0.2941 implies` Thus 54.23%
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