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The rate constant for a forward reaction...

The rate constant for a forward reaction in a reversible reaction `(K_(eq) = 10^(6))` is `10^(2)` . Calculate rate constant for its backward reaction

A

`10^(4)`

B

`10^(-4)`

C

`10^(-6)`

D

`10^(6)`

Text Solution

Verified by Experts

The correct Answer is:
B
`K_(c)=(K_(f))/(K_(b))`
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