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N(2)O(4) is dissociated to 33% and 50% a...

`N_(2)O_(4)` is dissociated to 33% and 50% at total pressure `P_(1) and P_(2)` atm respectively. The ratio of `(P_(1))/(P_(2))` is :

A

`(7)/(4)`

B

`(7)/(3)`

C

`(8)/(3)`

D

`(8)/(5)`

Text Solution

Verified by Experts

The correct Answer is:
C
`underset(1-alpha)underset(1)(N_(2)O_(4(g))) harr underset(2alpha)underset(0)(NO_(2(g)))`
`K_(P)=((""^(n)NO_(2))^(2))/(""^(n)N_(2)O_(4)) xx [(P)/(epsilon n)]^(1)`
For 33% dissociation
`K_(P)=((2 xx 33)^(2))/(67) xx [(P_(1))/(133)]^(1)` …...(1)
For 50% dissociation `K_(P)=((2 xx 50)^(2))/(50) xx ((P_(2))/(150))^(1)`
`:. (P_(1))/(P_(2))=(133 xx 67 xx (2 xx 50)^(2))/((2 xx 33)^(2) xx 150 xx 50)=(8)/(3)`
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