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For the cqiuilibrium LiCI 3NH(3(s)) LiCI...

For the cqiuilibrium LiCI `3NH_(3(s))` LiCI `NH_(3(s)) + 2NH_(3(g)), ` Kp = 9 `atm^(2) "at" 37^(@)`C. A 5 lires vesel contains 0. 1 mole of LiCI `NH_(3)`. How many moles of `NH_(3)` should be added to the llask at this temperature to derive the backward reaction for completion ?

A

0.2

B

0.59

C

0.69

D

0.79

Text Solution

Verified by Experts

The correct Answer is:
D
Backward reaction to completion `implies` 0.1 moles of `4.CI.NH_(3)` is used `implies` 0.2 moles of `NH_(3)` is used after complection, still
`K_(P) =9 implies P_(NH_(3)) = 3 implies n_(NH_(3)) = 0.59`
`:.` Total moles to be added = 0.2 + 0.59 = 0.79
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