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Plots of log K Vs (1)/(T) plots shows an...

Plots of log K Vs `(1)/(T)` plots shows an intercept of 2 on y-axis with a slope of `45^(@)` for the studied reactions. Assuming that `Delta H^(@) and Delta S^(@)` as temperature independent, select the correct statement

A

`DeltaG^(@)= -2.75 K.cal`

B

`DeltaS^(@)= 4.606 cal`

C

`DeltaS^(@)= -4.606 cal`

D

K=100.8

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
`Delta G^(@)= -2.303 RT logK`
`DeltaH^(@)-T Delta S^(@)= -2.303 RT logK`
`log_(k)=((-Delta H^(@))/(2.303R))(1)/(T)+(DeltaS^(@))/(2.303R)`
slope= `(-DeltaH^(@))/(2.303R)=tan 45^(@)`
`DeltaH^(@)= -2.303 xx 2 xx 1= -4.606` cal
Intercept = `(DeltaS^(@))/(2.303R)=2`
`DeltaS^(@)=9.212 cal implies DeltaG_(P)=DeltaH^(@)=T Delta S^(@)`
`= -4.606-298 xx 9.212 xx 10^(-3)`
`DeltaG^(@) = -2.75` k cal
`log_(10)^(k)=(-DeltaG^(@))/(2.303RT)=(2.75 xx 10^(3) cal)/(2.303 x 2 xx 298)=2`
`K=10^(2)=100`
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