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What is K(p) for the equation 2Cl((g)) h...

What is `K_(p)` for the equation `2Cl_((g)) hArr Cl_((g))` ? When the system contains equal numberof `Cl_((g))` atom and `Cl_(2(g))` molecules at 1 bar and 300 k

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The correct Answer is:
2
`2Cl_((g)) harr Cl_(2(g)) implies ""^(n)Cl=""^(n)Cl_(2)` at equilibrium
`X_(Cl)=(1)/(2), PCl=P_("total")` mole fraction of = `Cl=(1)/(2), ""^(X)Cl_(2)=(1)/(2), PCl_(2)=P_("total")` mole fraction of `Cl_(2)=(1)/(2), PCl_(2) = P_("total") xx Cl_(2)=(1)/(2) :. K_(P)=(PCl_(2))/((PCl)^(2))=((1)/(2))/(((1)/(2))^(2))=2`
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