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The equilibrium constant for the ionisat...

The equilibrium constant for the ionisation of `RNH_(2(g))` in water as
`RNH_(2(g)) + H_(2)O_((l)) hArr "RNH"_(3(aq))^(+) + OH_((aq))^(-) ` is `8 xx 10^(-6) ` at `25^(@)` C . Find the pH of a solution at equilibrium when pressure of `RNH_(2(g)) ` is 0.5 bar.

A

`~~12.3`

B

`~~11.3`

C

`~~11.45`

D

`~~10.3`

Text Solution

Verified by Experts

The correct Answer is:
B
`K_(eq)=([RNH_(3)^(+)][OH^(-)])/([RNH_(2)]), 8 xx 10^(-6)=(x^(2))/(0.5)`
`x=2 xx 10^(-3)`, POH=2.7, pH=11.3
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