Home
Class 11
CHEMISTRY
The degree of dissociation is 0.4 at 400...

The degree of dissociation is 0.4 at 400 K and a I atm for the gaseous reaction: `PCI_(5(g)) hArr PCl_(3(g)) +Cl_(2(g))` : assuming ideal behaviour of gases, calculate the density of cquilibrium mixture at 400K and latm

A

4.54 `g//lit`

B

3.54 `g//lit`

C

5.54 `g//lit`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

`underset(1-0.4)underset(1)(PCl_(5)) harr underset(0.4)underset(0)(PCl_(3(g))) + underset(0.4)underset(0)(Cl_(2(g)))`
Total moles at equilibrium = 1.4
`("Normal molar mass of" PCl_(5)=i+alpha)/("Exp. Molar mass of" PCl_(5)=1.4)`
`(208.5)/("Exp. molar mass")=1.4`
`implies` Exp. molar mass (or) Molar mass of mix = `(208.5)/(1.4)`
Now using `Pv=(wRT)/(M) implies P=(dRT)/(M)`
`d=(pM)/(RT)=(1 xx 208.5)/(1.4 xx 0.0821 xx 400)=4.54 g//lit`
Promotional Banner

Similar Questions

Explore conceptually related problems

For the reaction PCl_(5(g)) harr PCl_(3(g)) + Cl_(2(g)) . Which of the graph "is"//"are" correct?

For the reaction PCl_(5(g)) hArr PCl_(3(g)) + Cl_(2(g)) the forward reaction at constant temperature is favoured by

For the reaction CO_((g)) + Cl_(2(g)) hArr COCl_(2(g)). The K_(p)//K_(c) is equal to

Consider the following reaction, PCl_(5) (g) hArr PCl_(3) (g) + Cl_(2)(g) the forward reaction at constant temperature is favoured by

Dissociation of PCI_(5) takes place on heating as follows: PCl_(5(g)) harr PCl_(3(g))+Cl_(2(g)) 'D' is the vapour density of PCI_(5) initially and 'd' is the vapour density of the equilibrium mixture. Which of the following graph is correct ( alpha = degree of dissociation).

At 27^(@)C, K_(p) value for the reversible reaction PCl_(5)(g)harrPCl_(3)(g)+Cl_(2)(g) is 0.65, calculate K_(c) .

For the equilibrium PCI_(5(g)) harr PCI_(3(g)) + CI_(2(g)) , K_c=(alpha^2)/((1-alpha)V) temperature remaining constant,

PCl_(5) dissociates as follows in a closed reaction vessel PCI_(5(g)) harr PCl_(3(g)) + Cl_((g)) . If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl_(5) is x, the partial pressure of PCI_(3) will be