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At some temperature and under a pressure...

At some temperature and under a pressure of 4 atm, `PCI_(5)` is 10% dissociated. Calculate the pressure at which `PCI_(5)` will be 20% dissociated, temperature remaining same

A

9.7 atm

B

0.97 atm

C

97 atm

D

7.9 atm

Text Solution

Verified by Experts

The correct Answer is:
B
`underset(1-alpha)underset(1)(PCl_(5(g))) harr underset(alpha)underset(0)(PCl_(3(g)))+underset(alpha)underset(0)(Cl_(2(g)))`
`Kp=(alpha^(2))/((1-alpha))[(p)/(1+alpha)]^(1)`
Since, Kp remains constant and therefore equating for
`alpha=0.1` at p=4atm and `alpha=0.2` at p=p atm
`((0.1)^(2))/(0.9) xx (4)/(1.1)=((0.2)^(2) xx p)/(0.8 xx 1.2) implies p=0.97` atm
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