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The values of Kp(1) and Kp(2) for the re...

The values of `Kp_(1) and Kp_(2)` for the reaction given below are in the ratio 2: 1. If degree of dissociation of X and A are equal, then total pressure of equilibrium (1) and cquilibrium (2) are in the ratio
`X hArr Y + Z , Kp_(1) : A hArr 2B : Kp_(2) `

Text Solution

Verified by Experts

The correct Answer is:
8
`underset(1-alpha_(1))(X) harr underset(alpha_(1))(Y)+underset(alpha_(1))(Z)`
`Kp_(1)=(((alpha_(1))/(1+alpha_(1)).p_(1)) xx ((alpha_(1))/(1+alpha_(1)).p_(1)))/(((1-alpha_(1))/(1+alpha_(1)) xx p_(1)))`
`Kp=(alpha_(1)^(2) xx p_(1))/(1-alpha_(1)^(2))` ...(1)
`underset(1-alpha_(1))(A) harr underset(2alpha_(1))(2B), Kp_(2)`
`Kp_(2)=(((2alpha_(1))/(1+alpha_(1)) xx p_(2))^(2))/((1-alpha_(1))/(1+alpha_(1)) xx p_(2)), Kp_(2)=(4alpha_(1)^(2) xx p_(2))/(1-alpha_(1)^(2))` ...(2)
`((1))/((2))(Kp_(1))/(Kp_(2))=(1)/(4) xx (p_(1))/(p_(2)) implies (p_(1))/(p_(2))=4 xx (Kp_(1))/(Kp_(2))=4 xx 2=8`
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