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DeltaH^(0) for a reaction F(2) + 2HCl ra...

`DeltaH^(0)` for a reaction `F_(2) + 2HCl rarr 2HF + Cl_(2)` is given as `-352.8 kJ. Delta H_(f)^(0)` for HF is `-268.3 KJ mol^(-1)`, then `Delta H_(f)^(0)` of HCl would be

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`Delta H = H _(P) - H _(R) = 2 H _(HF) - 2H _(HCl)`
`=- 352.8 kJ = 2 (0268.3) - 2 (H _(HCl))`
`2 (H _(HCl))=-536.6 + 352.8 =-183.8kJ.`
(or) `H _(HCl) =-91.9 kJ mol ^(-1).`
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