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Heats of combustion of benzene, carbon a...

Heats of combustion of benzene, carbon and hydrogen are `- 782, -94, -68 kcal mol^(-1)` respectively. Calculate heat of formation of benzene. 

Text Solution

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The given data `C _(6) H _(6 (s)) + 15//2 O _(2 (g)) to 6 CO _(2 (g)) + 3H _(2 ) O _((l)) , Delta H _(1) =- 782K.cal`
`C _((s)) + O _(2 (g)) to CO _(2(g)) , Delta H _(2) =- 94 Kcal`
`H _(2 (g)) + (1)/(2) O _(2 (g)) to H _(2) O _((l)) , Delta H _(3) =- 68 kcl`
The required equation is
`6C _((s)) + 3 H _(2(g)) to C _(6) H _(6(l)) , Delta H =?`
Heat of formation of benzene =
`Delta H =- Delta H _(1) + 6 Delta H _(2) + 3 Delta H _(2) = + 14kcal`
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