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Latent heat of fusion of ice is 6 kJ mol...

Latent heat of fusion of ice is `6 kJ mol^(-1)`. Calculate the entropy change in the fusion of ice. 

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Change in entropy,`Delta S = q _(rev)//T`
`q _(rev) =` Latent heat of fusion `=6 kJ mol ^(-1) = 6000 j mol ^(-1) T =` Freezing point of water = 273K.
`Delta S = (6000)/(273) = 21.98 JK^(-1) mol ^(-1) (or)`
`Delta S = (6000)/(273 xx 18) = 1.22 JK ^(-1) g ^(-1)`
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