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The equilibrium constant of a reaction i...

The equilibrium constant of a reaction is 73. Calculate standard free energy change.

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Equilibrium constant K is related to `Delta G^(@)` as, `Delta G ^(@) =- 2.303 RT` log K. Substituting the values, `K= 73, T = 298K and R = 8.314 JK^(-1)mol^(-1)`
`Delta G ^(@) =- 2.303 xx 8.314 xx 298 xx log _(10 ) ^(73) =-10, 632 J mol ^(-1)`
Standard free energy change `= - 10.632 kJ mol^(-1)`
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