Define heat of neutralisation. Write the basic equation. Why the heat liberated by the neutralisation of a weak acid is less than `57.3 kJ mol^(-1)` ?

Heat released in neutralisation of 1 mole of HF with excess NaoH is

How does heat of neutralisation value change with the chemical nature of acid and base?

Heat of neutralisation of H_2SO_4 with NaOH is - x KJ. Then the heat of ionisation of water is

Heat of neutralisation of a polybasic acid by strong base is -54.8 kcal mol^(-1) . What is basicity of the acid?

The heat of ionisation of weak acid and a weak base are .x. and .y. k.cals. Then the heat of neutralisation of that weak acid and weak base is ....K.cal.

The enthalpy of neutralization of weak monoprotic acid, HA in 1M solution with a strong base is -55.95 KJ/mol if the unionised acid requires 1.4 KJ/mol heat for its complete ionization and enthalpy of neutralisation of the strong monobasic acid with a strong monoacidic base is = -57.3 KJ/mol. What will be % ionization of weak acid in molar solution is

Heats of ionisation of acetic acid and ammonium hydroxide are x kJ mol^(-1) and y kJ mol^(-1) . Heat of neutralisation of HCl and NaOH is z kJ mol^(-1) . Calculate the heat when acetic acid is neutralised with ammonium hydroxide. (z-(x+y)kJ mol^(-1))

When IM H_2SO_3 is completely neutralised by sodium hydroxide, the heat liberated is 114.64 KJ. Enthalpy of neutralisation in KJ is?