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N(2) + 3H(2) rarr 2NH(3), Delta H = - 46...

`N_(2) + 3H_(2) rarr 2NH_(3), Delta H = - 46K`. Cals. From the above reaction, heat of formation of ammonia is

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`Delta H _(3) + Delta H _(2) // 2-3 Delta H _(1) //2`
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