A sound wave of amplitude of 3 cm starts towards right from origin and gets reflected at a rigid wall after a second. If the velocity of the wave is `340 ms^(-1)` and it has a wavelength of 2m, deduce the equations of the incident and reflected waves.

Explanation

`A=3xx10^(-2)m,V=340 ms^(-1), lambda=2m`
`:.` The incident wave towards right is given by `y=A"sin"(2pi)/(lambda)(vt-x)=3xx10^(-2)sin pi(340t-x)`
The reflection at the rigid wall will produce a phase difference of `pi`.
`:.` The reflected wave is give by
`y=3xx10^(-2)sin(340 pit+pix+pi)`
`y=-3xx10^(-2) sinpi(340t+x)` towards left.