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Both the strings, shown in figure, are made of same material and have same cross section. The pulleys are light. The wave speed of a transverse wave in the string AB is `u_(1)` and in it is `v_(2)`. Then `v_(1)//v_(2)` is

A

1

B

2

C

`sqrt(2)`

D

`1//sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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