Home
Class 12
PHYSICS
The ends of a stretched wire of length '...

The ends of a stretched wire of length 'L' are fixed at x = 0 and x = L. In one experiment, the displacement of the wire is `y_(1) = A "sin"(pi x)/(L) sin wt` and the energy is `E_(1)` and in another experiment its displacement is `y_(2)=A "sin" (2pi x)/(L) sin 2 wt` and the energy `E_(2)` then

A

`E_(2)=E_(1)`

B

`E_(2)=2E_(1)`

C

`E_(2)=4E_(1)`

D

`E_(2)=16E_(1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • WAVES

    AAKASH SERIES|Exercise EXERCISE-III (Strings (Speed of travelling wave))|15 Videos

  • WAVES

    AAKASH SERIES|Exercise EXERCISE-III (Velocity of Sound :)|4 Videos

  • WAVES

    AAKASH SERIES|Exercise EXERCISE-II (Doppler Effect : )|23 Videos

  • WAVE OPTICS

    AAKASH SERIES|Exercise PROBLEMS (LEVEL - II)|20 Videos

  • WAVES OPTICS

    AAKASH SERIES|Exercise EXERCISE -III (POLARISITION)|10 Videos