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A sound source is falling under gravity....

A sound source is falling under gravity. At some time = 0, the detector lies vertically below the source at a depth H as shown. If v is the velocity of sound and `f_(0)` is frequency of the source, then the apparent frequency recorded after t = 2s is

A

`f_(0)`

B

`(f_(0)(v+2g))/(v)`

C

`(f_(0)(v-2g))/(v)`

D

`f_(0)((v)/(v-2g))`

Text Solution

Verified by Experts

The correct Answer is:
D
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