Find the kinetic energy, potential energy and total energy in first and second orbit of hydrogen atom if potential energy in first orbit is taken to be zero.

Explanation

`E_(1) = .13.60`e V , `K_(1) = - E_(1) =` 13.60eV
`U_(1) = 2E_(1) = -27.20`eV
`E_(2) = -3.40"eV " K_(2) = 3.40`eV and `U_(2) = `-6.80 eV
Now, `U_(1)` = 0, i.e., potential energy has been increased by 27.20eV
So, we will increase U and E in all energy states by 27 .20e V while kinetic energy will remain unchanged.
HenceK(eV), U(eV),E(eV)Firstorbitare 13.6,0, 13.6 in Second orbit 3.40, 20.40, 23.80