The ratio of gravitational force and electrostatic repulsive force between two electrons is approximatly (gravitational constant `=6.7 xx 10^(-11)Nm^(2)//Kg^(2)`, mass of an electron `=9.1 xx 10^(-31)kg`, charge on an electron `=1.6 xx 10^(-19)C`)
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The ratio of gravitational force and electrostatic repulsive force between two electrons is approximately (gravitational constant =6.7xx10^(-11)Nm^2//kg^2 , mass of an electron =9.1xx10^(-31)kg , charge on an electron = 1.6 xx 10^(–19) C)
If mass of an electron is 9.11xx10^(-31) kg, how many electrons will weight 2 kg?
The mass of an electron is 9.11xx10^(-31)kg . How many elecrons would make 1kg?
The rest mass of an electron is 9.11xx10^(-31) kg. Molar mass of the electron is
The ratio of electrostatic and gravitational force acting between electron and proton separated by a distance 5 xx 10^(-11)m , will be (charge on electron = 1.6 xx 10^(-19)C , mass of electron = 9.1 xx 10^(-31) kg , mass of proton = 1.6 xx 10^(-27) kg, G = 6.7 xx 10^(-11) N - m^(2)//kg^(2) )
An electron is moving with a velocity of 10^(7) m s^(-1) . Find its energy in electron volts. (Mass of electron =9.1xx10^(-31) kg and charge of electron =1.6xx10^(-19) C )
Calculate the gravitational force of attraction between two spherical bodies, each of mass 1kg placed at 10m apart (G = 6.67 xx 10^(-11)Nm^(2)//kg^(2)) .
Find the time of relation between collision and free path of electrons in copper at room temperature .Given resistance of copper = 1.5xx 10^(-8) Omega m number density of electron in copper = 8.5 xx 10^(28)m^(-3) charge on electron = 1.6 xx 10^(19)C , mass of electrons = 9.1 xx 10^(-19) kg Drift velocity of free electron = 1.6 xx 10^(-4)ms^(-1)
