A point is in motion along a cubic parabola `12y = x^(3)` . Which of its coordinates changes faster ?

A particle is in motion along a curve 12y= x^(3) . The rate of change of its ordinate exceeds that of abscissa in

A particle moves along the curve 12y=x^(3) . . Which coordinate changes at faster rate at x=10 ?

A particle moves along the straight line y=3x+5 . Which coordinate changes at faster rate?

A particle moves along the straight line y= 3x+5 . Which coordinate changes at a faster rate ?

A point is in motion along a hyperbola y=(10)/(x) so that its abscissa x increases uniformly at a rate of l unit per second. Then, the rate of change of its ordinate, when the point passes through (5, 2)

The point on the parabola y^(2)=4x at which the abscissa and ordinate change at the same rate is

The focal distance of a point on the parabola y^(2)=8x is 10 .Its coordinates are

The points on the curve 12y = x^(3) whose ordinate and abscissa change at the same rate, are

The point(s) on the curve y=x^(2) ,at which y -coordinate is changing six times as fast as x - coordinate is/are (a) (2,4) (b) (3,9) (c) (3,9) , (9,3) (d) (6,2)

Find the point on the parabola y^(2)=12x at which ordinate is 3 times its abscissa.