The velocity of a body in rectilinear motion is determined by the formula `v = 3t + t^(2)`. What acceleration will the body have 4s after the start ?

At t=0 , a body starts from origin with some initial velocity. The displacement x(m) of the body varies with time t(s) as x=-(2//3)t^2+16t+2 . Find the initial velocity of the body and also find how long does the body take to come to rest? What is the acceleration of the body when it comes to rest?

The displacement of body is given by s = 4 + 2t^4 . The acceleration of the body at the end of 1 s from the start is :

Frame the formula: final velocity (v) of a body in linear motion is equal to the sum of its initial velocity (u) and the product of acceleration (a) and time (t).

If S=6t^(2)-t^(3) , then the body comes to rest after time t=

The velocity of a body at time t = 0 is 10sqrt2m//s in the north-east direction and it is moving with an acceleration of 2m//s directed towards the south. The magnitude and direction of the velocity of the body after 5 sec will be

The displacement of a body at any time t after starting is given by s=15t-0.4t^(2) . The velocity of the body will be 7ms^(-1) after time :

The motion of a particle is described as S =2-3t+4t^(3) what is the acceleration of the paricle at the point where its velocity is zero ?