There are three events A, B and C one of which must , and only one can happen, the odd are 7 to 3 against A and 5 to 9 for B. Find the odds, against C.

There are three events A,B,C one of which must,and only one can,happen,the odds are 8 to 3 against A,5 to 2 against B: Find the odds against C .

There are three events A,B,C one of which must and only one can happen; The odds are 8 to 3 against A,5 to 2 against B; find the odds against C.

There are three events A,B and C one of which and only one can happen.The odds are 7 to 3 against A and 6 to 4 against B. The odds against C are

There are three events A, B and C, one of which must, and only one can happen. The odds against the event A are 7:4 and odds against event B are 5:3 . Find the odds against event C.

There are three evens E_(1),E_(2) and E_(3) one of which must, and only one can happen. The odds are 7 to 4 against E_(1) and 5 to 3 against E_(2) . Find odds against E_(3) .

The chance of an event happening is the square of the chance of a second event but the odds against the first are the cube of the odds against the second.The chances of the events are

If the probability of occurrence of an event is (2)/(13). Find the odds against the event.

For the three events A, B and C, P(exactly one of the events A or B occurs) = P(exactly one of the events B or C occurs) =P(exactly one of the events C or A occurs)= p and P(all the three events occur simultaneously) = p^2, where 0ltplt1/2. Then, find the probability of occurrence of at least one of the events A, B and C.