Home
Class 11
CHEMISTRY
If the energy of H-atom in the ground st...

If the energy of H-atom in the ground state is -E, the velocity of photo-electron emitted when a photon having energy `E_p` strikes a stationary `Li^(2+)` ion in ground state, is given by:

A

`v= sqrt((2(E_P-E))/(m))`

B

`v= sqrt((2(E_P+E))/(m))`

C

`v= sqrt((2(E_P-9E))/(m))`

D

`v= sqrt((2(E_P-3E))/(m))`

Text Solution

Verified by Experts

The correct Answer is:
C
Work function for `Li^(2+) = 9E`
`E_p = w + 1/2 mv^2 , E_p = 9E + 1/2 mv^2`
`V= sqrt((2(E_p - 9E))/(m))`
Promotional Banner

Similar Questions

Explore conceptually related problems

The energy of electron in the ground state of Hydrogen atom is -13. 6ev. The kinetic energy of the electron is the 4th orbit is

The radius of hydrogen atom in the ground state is 0.53 Å, the radius of Li^(2+) in the similar state is

The radius of hydrogen atom in the ground state is 0.53 Å, the radius of Li^(2+) in the similar state is

The radius of hydrogen atom in the ground state is 0.53 Å , the radius of Li^(2+) in the similar state is

In a hydrogen atom, if energy of an electron in ground state is 13.6 eV, then the energy in the 2nd excited state is

In a hydrogen atom, if energy of an electron in ground state is 13.6eV, then the energy in the nearest excited state is

If the ratio of energies of electron in the excited states of H and Li^(2+) is 1 : 9, the radius ratio of electron in the same excited states of H and Li^(2+) is

The potential energy of the electron present in the ground state of Li^(2+) ion is represented by

The potential energy of the electron present in the ground state of Li^(+2) ion is represented by :