The energy of a I, II and III energy levels of a certain atom are E, `(4E)/(3)` and 2E respectively A photon of wavelength `lambda` is emitted during a transition from III to I. What will be the wavelength of emission for transition II to I?

Options

A. `lambda/2`
B. `lambda`
C. `2lambda`
D. `3lambda`

Answer

D

Explanation

For II to I transition
`Delta E = (4E)/(3) - E = (hc)/(lambda_(II to 1)) ` or `E= (hc)/(lambda)`
`therefore (hc)/(3 xx lambda) = (hc)/(lambda_(II -I)) , lambda_(II-I) = 3 lambda`