A metal is irradiated with a radiation of wavelength 300 nm. Then photo electrons found to have velocity of `3.7 xx 10^5 `m/s. When a graph is drawn between K.E of photo electrons and frequency of radiation a straight line is obtained cutting X-axis.
Difference between incident frequency and threshold frequency is

Options

A. `9.4xx10^(13)` Hz
B. `8.5xx10^(22)` Hz
C. `9.4xx10^(12)` Hz
D. `8.4xx10^(10) Hz`

Answer

A

Explanation

`upsilon - upsilon_0 =(6.625xx10^(-19))/(6.625xx10^(13)) -9.09 xx 10^(14)`
`=9.4xx10^(23) Hz`