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Given r(n+1) - r(n-1)=2r(n) where rn , r...

Given `r_(n+1) - r_(n-1)=2r_(n)` where `r_n , r_(n-1) , r_(n+1)` are Bohr radius for hydrogen atom in `n^(th)` , `(n+1)^(th)` and `(n-1)^(th)` shell respectively . Calculate the value of n.

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The correct Answer is:
2
`(n+1)^2 - (n-1)^2 = 2n^2 , n=2`
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