`Be^(+3)` and a proton are accelerated by the same potenatial, their de-Broglie wavelengths have the ratio (assume mass of proton = mass of neutron)

Options

A. `1:2`
B. `1:4`
C. `1:1`
D. `2:1`

Answer

D

Explanation

`(lambda_1)/(lambda_2)= sqrt((m_2)/(m_1))`