de-Broglie proposed the dual nature of electron and put forward his wave concept. The wave length of electron in an orbit was given by `lambda =h/(mv)`
The de-Broglie.s wavelength `(lambda)` of the electron subjected to an accelerating potential of V volts is given by

Options

A. `(K.E)/(h)`
B. `(2K.E)/(h)`
C. `(K.E)/(2h)`
D. `(h)/(2K.E)`

Answer

B

Explanation

`lambda = (h)/(mv) , v = (upsilon)/(lambda) =(upsilon)/(h//mupsilon) = (m upsilon^2)/(h) = (2K.E)/(h)`