The wavelength of a certain line in Balm...

The wavelength of a certain line in Balmer Series is observed to be 4329 Å. To what value of .n. does this correspond ? `(R_(H) = 109678cm^(-1))` (Z=1)

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The correct Answer is:

5

`1/(lambda) = R_H Z^2 [1/(n_1^2) - 1/(n_2^2)]`
`implies 1/(4329xx10^(-8)) = 1.09678 xx 10^5 [1/4 - 1/(n_2^2)]`
`therefore n_2 = 5`

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