The chlorine atom has

Options

A. 6 electrons with l = 0
B. 11 electrons with l=1
C. 5 orbitals with m = 0
D. 2 orbitals with m + 1

Answer

A, B, C, D

Explanation

Chlorine `(Z= 17 ) E.c. = 1s^2 2s^2 2p^6 3s^2 3p^5`,

For .s. `e^- , l=0`
For `.p. e^(-) , m` values are `+1 , 0 , -1`